## Minimum value by Vivek Pandey

Find the minimum value of    over  Solution: Let , . Here the function  is continuous and differentiable on . Therefore   For critical points , which implies   The first equation gives The second equation gives or squaring we get , for some . Now we get the values…

## Function

: Show that the function given by is a one-to-one function Solution: We know that a function is a one-to-one function iff for all Case 1: Let be even integers Case 2: Let be odd integers Case 3: Let be odd and be even then and i.e. is a false…

## Range of a function

: Find the range of the function given by . Solution: The domain of the given function is closed interval . Since this function  is continuous on the  closed interval [0,1] , therefore it attains its bound (the greatest and least value), somewhere in the closed interval. By Fermat’s…

## Trigonometric Inequalities

: Show that for each real. Sol. Consider the equation .     Taking +ve   sign, we get, which is not possible Taking – ve sign  we get, , which is again not possible Hence the equation     has no solution. Now consider the function The function is continuous…